This is a test by Astrageldon!
And below are the Maxwell's equations in their differential form:
\[ \newcommand{\bs}{\boldsymbol} \left\{ \begin{aligned} \bs{\nabla}\cdot\bs{E}&=\frac{\rho}{\varepsilon_0}\\ \bs{\nabla}\times\bs{E}&=-\frac{\partial\bs B}{\partial t}\\ \bs{\nabla}\cdot\bs{B}&=0\\ \bs{\nabla}\times\bs{B}&=\mu_0\bs{j}+\mu_0\varepsilon_0\frac{\partial\bs E}{\partial t} \end{aligned} \right. \]
And below is a ...
Doro!!!
